ГДЗ по химии 11 Класс класс Габриелян О.С., Остроумов И.Г., Сладков С.А. упражнение - §38. Кислород и озон. Пероксид водорода, задание 8

$$\begin{gathered} \mathrm{а}) \mathrm{S} + 6{\mathrm{HNO}}_3 \to {\mathrm{H}}_2{\mathrm{SO}}_4 + 6{\mathrm{NO}}_2\uparrow + 2{\mathrm{H}}_2\mathrm{O} \\ {\mathrm{S}}^0 —6\mathrm{e} \to {\mathrm{S}}^{+6} | 1 \\ {\mathrm{N}}^{+5} + 1\mathrm{e} \to {\mathrm{N}}^{+4} | 6 \end{gathered}$$

$$\begin{gathered} \mathrm{б}) {\mathrm{H}}_2\mathrm{O} + 2\mathrm{KI} + {\mathrm{O}}_3 \to {\mathrm{O}}_2\uparrow + {\mathrm{I}}_2 + 2\mathrm{KOH} \\ 2{\mathrm{I}}^{—} —2\mathrm{e} \to {{\mathrm{I}}_2}^0 | 1 \\ {\mathrm{O}}^0 + 2\mathrm{e} \to {\mathrm{O}}^{—2} | 1 \end{gathered}$$

$$\begin{gathered} \mathrm{в}) 4\mathrm{Fe}{\left(\mathrm{OH}\right)}_2 + {\mathrm{O}}_2 + 2{\mathrm{H}}_2\mathrm{O} \to 4\mathrm{Fe}{\left(\mathrm{OH}\right)}_3 \\ {\mathrm{Fe}}^{+2} —\mathrm{e} \to {\mathrm{Fe}}^{+3} | 4 \\ {{\mathrm{O}}_2}^0 +4\mathrm{e} \to 2{\mathrm{O}}^{—2} | 1 \end{gathered}$$

$$\begin{gathered} \mathrm{г}) 4{\mathrm{NO}}_2 + {\mathrm{O}}_2 + 2{\mathrm{H}}_2\mathrm{O} \to 4{\mathrm{HNO}}_3 \\ {\mathrm{N}}^{+4} —\mathrm{e} \to {\mathrm{N}}^{+5} | 4 \\ {{\mathrm{O}}_2}^0 +4\mathrm{e} \to 2{\mathrm{O}}^{—2} | 1 \end{gathered}$$

$$\begin{gathered} \mathrm{д}) 3{\mathrm{OF}}_2 + 4{\mathrm{NH}}_3 \to 6\mathrm{HF} + 2{\mathrm{N}}_2 + 3{\mathrm{H}}_2\mathrm{O} \\ 2{\mathrm{N}}^{—3} —6\mathrm{e} \to {{\mathrm{N}}_2}^0 | 4 \\ {\mathrm{O}}^{+2} +4\mathrm{e} \to {\mathrm{O}}^{—2} | 6 \end{gathered}$$

$$\begin{gathered} \mathrm{е}) 5{\mathrm{K}}_2{\mathrm{O}}_2 + 8{\mathrm{H}}_2{\mathrm{SO}}_4 + 2{\mathrm{KMnO}}_4 \to 5{\mathrm{O}}_2 + 2{\mathrm{MnSO}}_4 + 6{\mathrm{K}}_2{\mathrm{SO}}_4 + 8{\mathrm{H}}_2\mathrm{O} \\ {\mathrm{Mn}}^{+7} +5\mathrm{e} \to {\mathrm{Mn}}^{+2} | 5 \\ 2{\mathrm{O}}^{—1} —2\mathrm{e} \to {{\mathrm{O}}_2}^0 | 2 \end{gathered}$$

$$\begin{gathered} \mathrm{ж}) {\mathrm{H}}_2{\mathrm{O}}_2 + {\mathrm{Ag}}_2\mathrm{O} = 2\mathrm{Ag} + {\mathrm{H}}_2\mathrm{O} + {\mathrm{O}}_2 \\ 2{\mathrm{O}}^{—1} —2\mathrm{e} \to {{\mathrm{O}}_2}^0 | 1 \\ 2{\mathrm{Ag}}^{+1} + 2\mathrm{e} \to 2{\mathrm{Ag}}^{0 } | 1 \end{gathered}$$

$$\begin{gathered} \mathrm{з}) 4{\mathrm{H}}_2{\mathrm{O}}_2 + {\mathrm{H}}_2\mathrm{S} \to {\mathrm{H}}_2{\mathrm{SO}}_4 + 4{\mathrm{H}}_2\mathrm{O} \\ {\mathrm{S}}^{—2} —8\mathrm{e} \to {\mathrm{S}}^{+6} |1 \\ 2{\mathrm{O}}^{—1} +2\mathrm{e} \to 2{\mathrm{O}}^{—2} |4 \end{gathered}$$

$$\begin{gathered} \mathrm{и}) {\mathrm{H}}_2{\mathrm{O}}_2 + \mathrm{HClO} \to \mathrm{HCl} + {\mathrm{H}}_2\mathrm{O} + {\mathrm{O}}_2 \\ {\mathrm{Cl}}^{+1} —2\mathrm{e} \to {\mathrm{Cl}}^{—1} |1 \\ 2{\mathrm{O}}^{—1} +2\mathrm{e} \to 2{\mathrm{O}}^{—2} |1 \end{gathered}$$

$$\begin{gathered} \mathrm{к}) 2{\mathrm{HIO}}_3 + 5{\mathrm{H}}_2{\mathrm{O}}_2 = {\mathrm{I}}_2 + 5{\mathrm{O}}_2 +6{\mathrm{H}}_2\mathrm{O} \\ 2{\mathrm{I}}^{+5} +10\mathrm{e} \to {{\mathrm{I}}_2}^0 | 1 \\ 2{\mathrm{O}}^{—1} —2\mathrm{e} \to {{\mathrm{O}}_2}^{{}_0} | 5 \end{gathered}$$

$$\begin{gathered} \mathrm{л}) 2{\mathrm{FeSO}}_4 + {\mathrm{H}}_2{\mathrm{O}}_2 + {\mathrm{H}}_2{\mathrm{SO}}_4 = {\mathrm{Fe}}_2{\left({\mathrm{SO}}_4\right)}_3 + 2{\mathrm{H}}_2\mathrm{O} \\ {\mathrm{Fe}}^{+2} +1\mathrm{e} \to {\mathrm{Fe}}^{+3} | 2 \\ 2{\mathrm{O}}^{—1} +2\mathrm{e} \to 2{\mathrm{O}}^{—2} | 1 \end{gathered}$$

$$\begin{gathered} \mathrm{м}) 2\mathrm{KI} + {\mathrm{H}}_2{\mathrm{O}}_2 = {\mathrm{I}}_2 + 2\mathrm{KOH} \\ 2{\mathrm{I}}^{—1} —2\mathrm{e} \to {{\mathrm{I}}_2}^0 | 1 \\ 2{\mathrm{O}}^{—1} +2\mathrm{e} \to 2{\mathrm{O}}^{—2} | 1 \end{gathered}$$